文本示例

Certainly! Here's an example of a Java function that can handle the login functionality for a website:

```java
import java.util.Scanner;

public class LoginWindow {
public static void main(String[] args) {
// Simulating a login window
showLoginWindow();
}

public static void showLoginWindow() {
Scanner scanner = new Scanner(System.in);

System.out.println(\"Welcome to the Login Window!\");
System.out.println(\"-----------------------------\");

System.out.print(\"Enter your username: \");
String username = scanner.nextLine();

System.out.print(\"Enter your password: \");
String password = scanner.nextLine();

// Validate the login credentials
boolean isLoggedIn = validateLogin(username, password);

if (isLoggedIn) {
System.out.println(\"Login successful! Welcome, \" + username + \"!\");
} else {
System.out.println(\"Invalid username or password. Please try again.\");
showLoginWindow(); // Recursive call to show the login window again
}

scanner.close();
}

public static boolean validateLogin(String username, String password) {
// Perform validation logic here (e.g., check against a database or API)
// Return true if the login is successful, false otherwise
// You can customize this method based on your specific requirements

// Example validation logic (username: \"admin\", password: \"password\")
return username.equals(\"admin\") \u0026\u0026 password.equals(\"password\");
}
}
```

In this example, the `showLoginWindow()` function displays a simple login window and prompts the user to enter their username and password. It then calls the `validateLogin()` function to check if the provided credentials are valid. If the login is successful, it displays a welcome message; otherwise, it prompts the user to try again.

Please note that this is a basic example, and in a real-world scenario, you would typically implement more robust validation and security measures.